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6x^2-6x+0.3456=0
a = 6; b = -6; c = +0.3456;
Δ = b2-4ac
Δ = -62-4·6·0.3456
Δ = 27.7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{27.7056}}{2*6}=\frac{6-\sqrt{27.7056}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{27.7056}}{2*6}=\frac{6+\sqrt{27.7056}}{12} $
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